如何使用C语言中的for循环将数组中的偶数和奇数分开？
#include void display(int a[], int size); int main(){ int size, i, a[10], even[20], odd[20]; int Ecount = 0, Ocount = 0; printf("enter size of array :
"); for(i = 0; i < size; i++){ scanf("%d", &a[i]); } for(i = 0; i < size; i ++){ if(a[i] % 2 == 0){ even[Ecount] = a[i]; Ecount++; } else{ odd[Ocount] = a[i]; Ocount++; } } printf("no: of elements comes under even are = %d
", Ecount); printf("The elements that are present in an even array is: "); display(even, Ecount); printf("no: of elements comes under odd are = %d
", Ocount); printf("The elements that are present in an odd array is : "); display(odd, Ocount); return 0; } void display(int a[], int size){ int i; for(i = 0; i < size; i++){ printf("%d \t ", a[i]); } printf("
"); }
