C/C++程序：计算以n的平方减去（n1）的平方为第n项的序列的和

开发运维 2023-08-29 宇宙之一粟 手机阅读

C/C++程序：计算以n的平方减去（n-1）的平方为第n项的序列的和

There are many types of series in mathematics which can be solved easily in C programming. This program is to find the sum of following of series in C program.

Tn = n2 - (n-1)2登录后复制

Sn = T1 + T2 + T3 + T4 + ...... + Tn

Input: 229137999 Output: 218194447登录后复制