oracle时间怎么转字符串
工作中编写过的一条语句 select * from Bt_Holiday whereto_char(Setting_DATE,YYYY)=Substr(2015-03-00,1,4) ANDto_char(Setting_DATE,MM)=Substr(2015-03-00,6, (instr(2015-03-00,-,1,2))-(instr(2015-03-00,-,1)+1)) Substr(2015-03-00,6, (in
<img src="https://img.mryunwei.com/uploads/2023/04/20230416080653781.jpg"><p>工作中编写过的一条语句</p>select * from Bt_Holiday whereto_char(Setting_DATE,'YYYY')=Substr('2015-03-00',1,4) AND
to_char(Setting_DATE,'MM')=Substr('2015-03-00',6, (instr('2015-03-00','-',1,2))-(instr('2015-03-00','-',1)+1))Substr('2015-03-00',6, (instr('2015-03-00','-',1,2))-(instr('2015-03-00','-',1)+1))
语句的意思是取得日期中的月。
to_char()函数功能,就是将数值型或者日期型转化为字符型。