获取MySQL的表中每个userid最后一条记录的方法

数据运维 2023-04-24 大树手机阅读

如下表： CREATE TABLE t1 (userid int(11) DEFAULT NULL,atime datetime DEFAULT NULL,KEY idx_userid (userid)) ENGINE=InnoDB DEFAULT CHARSET=utf8； CREATE TABLE t1 (userid int(11) DEFAULT NULL,atime datetime DEFAULT NULL,KE

                        <p>如下表：</p>

CREATE TABLE t1 ( userid int(11) DEFAULT NULL, atime datetime DEFAULT NULL, KEY idx_userid (userid) ) ENGINE=InnoDB DEFAULT CHARSET=utf8；

数据如下：

MySQL> select * from t1; +--------+---------------------+ | userid | atime | +--------+---------------------+ | 1 | 2013-08-12 11:05:25 | | 2 | 2013-08-12 11:05:29 | | 3 | 2013-08-12 11:05:32 | | 5 | 2013-08-12 11:05:34 | | 1 | 2013-08-12 11:05:40 | | 2 | 2013-08-12 11:05:43 | | 3 | 2013-08-12 11:05:48 | | 5 | 2013-08-12 11:06:03 | +--------+---------------------+ 8 rows in set (0.00 sec)

其中userid不唯一，要求取表中每个userid对应的时间离现在最近的一条记录．初看到一个这条件一般都会想到借用临时表及添加主建借助于join操作之类的．给一个简方法：

MySQL> select userid,substring_index(group_concat(atime order by atime desc),",",1) as atime from t1 group by userid; +--------+---------------------+ | userid | atime | +--------+---------------------+ | 1 | 2013-08-12 11:05:40 | | 2 | 2013-08-12 11:05:43 | | 3 | 2013-08-12 11:05:48 | | 5 | 2013-08-12 11:06:03 | +--------+---------------------+ 4 rows in set (0.03 sec)

Good luck!