使用MySQL的geometry类型处理经纬度距离问题的方法

建表 CREATE TABLE map ( id int(11) NOT NULL, address varchar(255) NOT NULL DEFAULT '', location geometry NOT NULL, PRIMARY KEY (id), SPATIAL KEY idx_location (location)) 插入 INSERT INTO map (id, address, location) VALUES

                        <p>建表</p>

CREATE TABLE map ( id int(11) NOT NULL, address varchar(255) NOT NULL DEFAULT '', location geometry NOT NULL, PRIMARY KEY (id), SPATIAL KEY idx_location (location) )

插入

INSERT INTO map (id, address, location) VALUES (1, 'somewhere', ST_GeomFromText('POINT(121.366961 31.190049)'));

注意必须使用 ST_GeomFromText 函数，且 POINT() 里面是：经度+空格+纬度

查询

1. 查看经纬度

SELECT address, ST_AsText(location) AS location FROM map;

2. 计算两点之间的距离

SELECT ST_Distance_Sphere(POINT(121.590347, 31.388094),location) AS distant FROM map;

算出来的结果，单位是米

注意现在POINT()里面经纬度之间是逗号分隔的

3. 查询距离小于1000m的地点，并由远及近排序

复制代码 代码如下:SELECT id, address, ST_Distance_Sphere(POINT(121.590347, 31.388094),location) AS distant FROM map WHERE ST_Distance_Sphere(POINT(121.590347, 31.388094),location) < 1000 ORDER BY distant;

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