declare @i int set @i='a' set @i=cast('a' as int) set @i=convert(int, 'a') print @i --输出结果为:将 varchar 值 'a' 转换为数据类型为 int 的列时发生语法错误。这一点与java不一样 declare @ch varchar(90) set @ch declare @i int set @
Declare @Id varchar(20) Declare @Name varchar(20) Declare Cur Cursor For select substring(id,0,7) as id,name from temp1 Open Cur Fetch next From Cur Into @Id,@Name While @@fetch_status=0 Begin Update
复制代码 代码如下: DECLARE @name VARCHAR(25) DECLARE @SQL VARCHAR(1000) DECLARE @logid INT DECLARE sysdatabase_name CURSOR FOR SELECT name FROM master.dbo.sysdatabases OPEN sysdatabase_name FETCH NEXT FROM sy
有时候我们需要想数据中写数据 declare@iint set@i=1 while@i30 begin insertintotable(id)values(@i) set@i=@i+1 end 有时候我们需要想数据中写数据 declare @i int set@i=1 while @i<30 begin insert into tab