脚本： 以下案例中都是 新库test1， 旧库test 。 1.对比表范围差异： select a.n_ts as "新库", a.n_tn as "新库表名", a.o_ts as "旧库", a.o_tn as "旧库表名" , case when a.n_tn is null then '新库缺表' when a.o_tn is null then '旧库缺表' else '表名一致' en