第一种:常规操作 SELECT SUM(ddd) AS count_days, CASEWHEN aa.days = 1AND aa.days 3 THEN '1-3'WHEN aa.days = 3AND aa.days 5 THEN '5-3'ELSE '5+'END AS groupby_daysFROM ( SELECT SUM(1) AS ddd, days FROM tour_grou
select语句完整语法: SELECT DISTINCT select_listFROM left_tablejoin_type JOIN right_tableON join_conditionWHERE where_conditionGROUP BY group_by_listHAVING having_conditionORDER BY order_by_conditionLIMIT li
mysql执行多表查询时报错: [SQL] SELECT * from (select e.account from employee eUNIONSELECT u.account from user uUNIONSELECT a.account from agent a)[Err] 1248 - Every derived table must have its own alias 这句话的意思